5n^2+n-510=0

Solution for 5n^2+n-510=0 equation:

5n^2+n-510=0

a = 5; b = 1; c = -510;
Δ = b2-4ac
Δ = 12-4·5·(-510)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-101}{2*5}=\frac{-102}{10}
=-10+1/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+101}{2*5}=\frac{100}{10}
=10
$